Answer:
1. nope
2. not sure
3. nope
Step-by-step explanation:
1.
-3(y - 1) > 3
-3y + 3 > 3
-3y > 0
y > 0
0 is not a solution since 0 is not greater than 0
2.
I'm not sure what this question means, is there a [tex]\geq or \leq[/tex] between the 4 and the 0?
3.
y + 8 < 2y + 8
8 < 2y - y + 8
8 - 8 < y
0 < y
0 is not a solution because 0 is not greater than 0
im confused- I prolly got something wrong.
