Methane Gas on reaction with Chlorine gas give Hydrogen Chloride gas and Carbon tetrachloride gas,
CH₄ + 2 Cl₂ → CCl₄ + 4 HCl
According to Balanced Equation,
44.8 L (2 moles) Cl₂ gas when consumed gives = 22.4 (1 mole) L CCl₄ gas
So, for 1.1 mL (0.001 L) Cl₂ gas, the amount of CCl₄ produced will be,
0.001 L Cl₂ gas on consumption will give = X L of CCl₄ gas
Solving for X,
X = (0.001 L × 22.4 L) ÷ 44.8 L
X = 0.005 L of Cl₄
Or,
X = 5 mL of CCl₄
Result:
On consumption of 1.1 mL of Cl₂ gas, 5 mL of CCl₄ gas is produced.
