If the equation written like this
[tex]log  x^{ \frac{1}{8} }  = - \frac{3}{2} 
then
 10^{- \frac{3}{2} } =  x^{ \frac{1}{8} } 
  (10^{- \frac{3}{2} })^{8} = ( x^{ \frac{1}{8} } )^{8}
x=  10^{-3*4} = 10^{-12}
x=10^{-12}
If the equation looks like this , then it has the solution
x=10^{-12}[/tex]