Respuesta :

JцstinBieber
A cross-section is a disc with radius [tex]8x^2[/tex]

[tex]V = \int_0^1 A(x)\, dx = \int_0^1 \pi\left(8x^2\right)^2 dx = \int_0^1 64 \pi x^4 = \left[\frac{64\pi}{5} x^5\right]_0^1 \\ \\ = \frac{64\pi}{5} [/tex]