jamalsanchez6498 jamalsanchez6498
  • 18-04-2018
  • Mathematics
contestada

Calculate work of a man holding a barbell at chest hight 2 m for 15 seconds?

Respuesta :

ali015
ali015 ali015
  • 18-04-2018
Answer: 0J

The equation for work is W=Fdcos(x), where w=work, f=force, d=displacement, and x=angle the force makes with the displacement vector.

Since the man is holding a barbell and the object, the barbell, isn't being displaced, d=0, making the work done equal to zero.
Answer Link

Otras preguntas

1. Rosa quiere que tú (escoger) el sofá para la sala. 2. La mamá de Susana prefiere que ella (estudiar) medicina. 3. Miranda insiste en que Luisa (ser) la candi
What is the solution to this system of equation? x=2y-4 7x+5y= -66
The American Civil War began in April 1861, when: A. Confederate and Union cavalry clash in disputed territory in Texas. B. Confederate forces fired upon and
A patient has been experiencing increasing fatigue in recent months, a trend that has prompted an echocardiogram. Results of this diagnostic test suggest that t
In what instances should a healthcare worker promote and practice better respiratory and hand hygiene?
If f(x) = 3x and g(x) = 1/x , what is the domain of (gºf)(x)?
Help please someone this literally makes no sense -9 - - =4
What were the main findings from hans selye’s general adaptation syndrome?
Why was the Exodus a key event for the Hebrews?
A piece of charcoal used for cooking is found at the remains of an ancient campsite. A 1.09 kg sample of carbon from the wood has an activity of 2020 decays per