AceGravity
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  • 18-04-2018
  • Mathematics
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mathstudent55
mathstudent55 mathstudent55
  • 18-04-2018
[tex] f(x) = \dfrac{4x - 3}{7} [/tex]

[tex] y = \dfrac{4x - 3}{7} [/tex]

[tex] x = \dfrac{4y - 3}{7} [/tex]

[tex] 7x = 4y - 3 [/tex]

[tex] 7x + 3 = 4y [/tex]

[tex] 4y = 7x + 3 [/tex]

[tex] y = \dfrac{7x + 3}{4} [/tex]

[tex] f^{-1}(x) = \dfrac{7x + 3}{4} [/tex]
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