Respuesta :

dwh2o13
the distance could be calculated as follows:
d = [tex] \sqrt{ (5-2)^{2} + (-4-3)^2} }[/tex]
d = [tex] \sqrt{ 3^{2} + (-7)^{2} [/tex]
d = [tex] \sqrt{58} [/tex]
WojtekR
[tex]A=(2,3)\qquad\qquad B=(5,-4)\\\\\\d(A,B)=\sqrt{(5-2)^2+(-4-3)^2}=\sqrt{3^2+(-7)^2}=\sqrt{9+49}=\\\\=\boxed{\sqrt{58}\approx7.61}[/tex]