Respuesta :
					                   The formula is
[tex]x=\frac{-b+\sqrt{b^2-4ac}}{2a}[/tex]
and
[tex]x=\frac{-b-\sqrt{b^2-4ac}}{2a}[/tex]
This gives you 2 results :) Just insert your values
					                
					             [tex]x=\frac{-b+\sqrt{b^2-4ac}}{2a}[/tex]
and
[tex]x=\frac{-b-\sqrt{b^2-4ac}}{2a}[/tex]
This gives you 2 results :) Just insert your values
					                   a= 2                b= -3          c= 1
firsly need to find discriminant.
D=b^2-4ac
(D= (-3)^2 - 4*2*1
D= 1)
If D>0, you get 2 solutions.
Then formula is:
x1,2 = -b ± √D
_____________
2 a
x1,2= -(-3)+-(1) = 3+-1 = 4 or = 2
____________ ______ ___ __
2*2 4 4 4
					                
					             firsly need to find discriminant.
D=b^2-4ac
(D= (-3)^2 - 4*2*1
D= 1)
If D>0, you get 2 solutions.
Then formula is:
x1,2 = -b ± √D
_____________
2 a
x1,2= -(-3)+-(1) = 3+-1 = 4 or = 2
____________ ______ ___ __
2*2 4 4 4
