Respuesta :

calculista
we have that
sin (7π/12)=?

we know that
7π/12=(π/4+π/3)
and 
sin(A+B)=sin(A)cos(B)+cos(A)sin(B)

then
sin(π/4+π/3)=sin(π/4)cos(π/3)+cos(π/4)sin(π/3)
sin(π/4+π/3)=(√2/2)(1/2)+(√2/2)(√3/2)-------> (√2/4)+(√6/4)---> (√2+√6)/4

the answer is (√2+√6)/4

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