tapetastic
tapetastic tapetastic
  • 21-01-2016
  • Mathematics
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If x+33=y+22 , then x3 = ____.

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Panoyin
Panoyin Panoyin
  • 21-01-2016
x + 33 = y + 22
    - 33        - 33
        x = y - 11

x³ = (y - 11)³
x³ = (y - 11)(y - 11)(y - 11)
x³ = (y(y - 11) - 11(y - 11))(y - 11)
x³ = (y(y) - y(11) - 11(y) + 11(11))(y - 11)
x³ = (y² - 11y - 11y + 121)(y - 11)
x³ = (y² - 22y + 121)(y - 11)
x³ = y²(y - 11) - 22y(y - 11) + 121(y - 11)
x³ = y²(y) - y²(11) - 22y(y) + 22y(11) + 121(y) - 121(11)
x³ = y³ - 11y² - 22y² + 242y + 121y - 1331
x³ = y³ - 33y² + 363y - 1331
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