okegbewilfred22
okegbewilfred22
21-02-2018
Mathematics
contestada
tanA+tanB=sin(A+B)/cosAcosB
Respuesta :
SatansGF
SatansGF
21-02-2018
Do you need to prove that it is equal?
If so:
SinA/cosA + sinB/cosB = (sinAcosB + sinBcosA)/cosAcosB
(SinAcosB + sinBcosA)/cosAcosB = (SinAcosB + sinBcosA)/cosAcosB
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