let one length be x and the other be y
x + x + y + y = 440
2x + 2y = 440
Divide by 2 through ...
x + y = 220
y = 220 - x
Area = xy
Area = x(220 -x) = 220x - [tex] x^{2} [/tex]
Given that that max length of x will be -b/2a
a = -1 b = 220
x = [tex] \frac{-220}{-2} [/tex] = 110
x = 110
y = 220 - 110 = 110
Therefore max area = 110 x 110 = 12100 square yards
