Respuesta :
x=pounds of Type A coffee
y=pounds of Type B coffee
QUANTITY EQUATION:
x+y=160
COST EQUATION:
$4.55x + $5.65y=$807.20
STEP 1:
Solve for one variable in equation one. Then substitute it in equation two.
x+y=160
subtract y from both sides of the equation
x=160-y
STEP 2:
substitute x=160-y in equation two
$4.55x + $5.65y=$807.20
4.55(160-y) + 5.65y=807.20
multiply 4.55 by everything in parentheses
(4.55*160)+(4.55*-y)+5.65y=807.20
728-4.55y+5.65y=807.20
combine like terms
728+1.10y=807.20
subtract 728 from both sides
1.10y=79.20
divide both sides by 1.10
y=72 pounds of type B coffee
STEP 3:
Substitute y=72 in either equation to solve for x
x+y=160
x+72=160
subtract 72 from both sides
x=88 pounds of type A coffee
ANSWER:
x=88 pounds of type A coffee
y= 72 pounds of type B coffee
CHECK:
Substitute answers for x & y into either equation to be sure it checks.
4.55x + $5.65y=$807.20
4.55(88)+5.65(72)=807.20
400.40+406.70=807.20
807.20=807.20
Hope this helps! :)
y=pounds of Type B coffee
QUANTITY EQUATION:
x+y=160
COST EQUATION:
$4.55x + $5.65y=$807.20
STEP 1:
Solve for one variable in equation one. Then substitute it in equation two.
x+y=160
subtract y from both sides of the equation
x=160-y
STEP 2:
substitute x=160-y in equation two
$4.55x + $5.65y=$807.20
4.55(160-y) + 5.65y=807.20
multiply 4.55 by everything in parentheses
(4.55*160)+(4.55*-y)+5.65y=807.20
728-4.55y+5.65y=807.20
combine like terms
728+1.10y=807.20
subtract 728 from both sides
1.10y=79.20
divide both sides by 1.10
y=72 pounds of type B coffee
STEP 3:
Substitute y=72 in either equation to solve for x
x+y=160
x+72=160
subtract 72 from both sides
x=88 pounds of type A coffee
ANSWER:
x=88 pounds of type A coffee
y= 72 pounds of type B coffee
CHECK:
Substitute answers for x & y into either equation to be sure it checks.
4.55x + $5.65y=$807.20
4.55(88)+5.65(72)=807.20
400.40+406.70=807.20
807.20=807.20
Hope this helps! :)