jonhandy99 jonhandy99

19-01-2018
Mathematics

contestada

what is the inverse of the function
[tex]f(x) = \frac{x + 1}{x} [/tex]

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lesliekolleroxrkcf lesliekolleroxrkcf

19-01-2018

y=(x+1)/x

x=y+1 / y

x=1/(y-1)

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