lilpalekitty
lilpalekitty lilpalekitty
  • 18-01-2018
  • Mathematics
contestada

Solve the differential equation: dy/dx = 4y2x
1
/3
A. 1
/
y
= 3x
4
/3 + C/
y
2
B. 1
/y
= 3x
4
/
3 + C
C. -
1
/
y
= 3x
4
/3 + C/
y
2
D. -
1
/y
= 3x
4
/
3
+ C

Respuesta :

vickyr12313
vickyr12313 vickyr12313
  • 18-01-2018
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what?

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