Answer:
Values of x will be [5 + √(-2)] and [5 - √(-2)]
Step-by-step explanation:
Thomas soled the equation (x² - 10x + 27) = 0 by completing the square.
x² - 2(5x) + 27 = 0
x² - 2(5x) + 25 - 25 + 27 = 0
(x - 5)² - 25 + 27 = 0
(x - 5)² + 2 = 0
(x - 5)² = - 2
(x - 5) = ±√(-2)
x = 5 ±√(-2)
Therefore, values of x will be [5 + √(-2)] and [5 - √(-2)].
