Answer:
x=-3 and x=+3
Step-by-step explanation:
x^2-9/x^2+6x+8 is equal to zero
We need to solve for x
[tex]\frac{x^2-9}{x^2+6x+8} =0[/tex]
Multiply the denominator on both sides
[tex]\frac{x^2-9}{x^2+6x+8} *x^2+6x+8 =0*x^2+6x+8[/tex]
x^2 - 9 =0
add 9 on both sides
x^2 = 9
Take square root on both sides
x = +- 3
So , x=-3 and x=+3
