josiemc9653 josiemc9653
  • 20-10-2017
  • Mathematics
contestada

For the curve y = ln(x 2 − 3), find the equation of the tangent line at (2, 0).

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jbmow
jbmow jbmow
  • 22-10-2017
y' = 2x/(x^2 -3)  y'(2) = 4
Using the point slope equation:
y-0 = 4(x-2)
y = 4x - 8
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