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What is the equation in point-slope form of a line that passes through the points (3, −5) and (−8, 4) ?





y−4=−911(x+8)




y+4=−911(x−8)




y−4=−15(x+8)




y+4=−15(x−8)
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Respuesta :

texaschic101
(3,-5)(-8,4)
slope = (4 - (-5) / (-8 - 3) = -9/11

y - y1 = m(x - x1)
slope(m) = -9/11
(-8,4)...x1 = -8 and y1 = 4
now we sub
y - 4 = -9/11(x - (-8) =
y - 4 = -9/11(x + 8) <===

YoungStudier
Point-Slope form:
y - y1 = m (x - x1)

First, we gotta find the slope of (3, -5) and (-8, 4)
m = 4 - (-5) / -8 - 3 = 4 + 5 / -8 + (-3) = 9 / -11 = [tex] -\frac{9}{11} [/tex]

Now all we gotta do is plug one of the points into Point-Slope Form
y - 4 = [tex]- \frac{9}{11} [/tex] (x - (-8))
y - 4 = [tex]- \frac{9}{11} [/tex] (x + 8)

So the answer choice would be the first one, or A.

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