Savageman6802 Savageman6802
  • 16-10-2017
  • Mathematics
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If we replace y with x2cos x and solve for y', we can conclude that the derivative is

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Аноним Аноним
  • 16-10-2017
y = x^2 cos x

y'  = x^2 * -sin x +  cos x * 2x

   =  2x cos x - x^2 sin x

  = x ( 2 cos x - x sin x)
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