darkcaster33 darkcaster33
  • 20-09-2017
  • Mathematics
contestada

Slope of y=x^2-2x-3 at P(2,-3)

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altavistard
altavistard altavistard
  • 26-09-2017
Recall that the derivative of this function, evaluated at x=2, is the slope of the tangent line to the graph of the function.

Thus, we begin by differentiating y=x^2-2x-3:

(dy/dx) = 2x -2

Evaluated at x=2, (dy/dx) = (2)(2)-2 = 4-2 = 2.

The slope of the tangent line to the graph of this function at (2, -3) is 2.
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