xcncxgnfxg9334 xcncxgnfxg9334
  • 19-09-2017
  • Mathematics
contestada

Find the root that is a real number. rootindex 4 startroot 4096 endroot

Respuesta :

jonathanjohnso1 jonathanjohnso1
  • 20-09-2017
the answer would be C.

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danielafalvarenga danielafalvarenga
  • 23-09-2019

Answer: 8

Step-by-step explanation:[tex]\sqrt[4]{4096}[/tex]

We need to factor this, so

[tex]4096|2\\2048|2\\1024|2\\512|2\\256|2\\128|2\\64|2\\32|2\\16|2\\8|2\\4|2\\2|2\\1[/tex]

[tex]4096 = 2^{12}[/tex]

We have to remember that [tex]x^{n+m}=x^{n}.x^{m}[/tex]

This way, we have [tex]\sqrt[4]{4096}=\sqrt[4]{2^{12}} = \sqrt[4]{2^{4}.2^{4}.2^{4}}  = 2.2.2=8[/tex]

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