6x² - x -12. This is a quadratic equation. Find its roots (Zeros):
x' = [-b+√(b²-4.a.c)]/2a and x" = [-b-√(b²-4.a.c)]/2a
x' = 3/2 and x" = - 4/3
remember : ax²+bx + c = a(x-x')(x-x')
Then 6x² -x - 12 = 6(x-3/2)(x+4/3) (Reduce to the same denominator and simplify after reduction):
(2x-3)(3x+4)
