find the zeros of thr function f (x)(x-2)^2 -9
 
											 
											Answer:
-4.449
4.449
Step-by-step explanation:
[tex](x-2)^2-9=0\\x^2-4x+4-9=0\\x^2-4x-2=0\\\frac{4+-\sqrt{4^2-4*1*(-2)} }{2*1} \\\frac{4-\sqrt{24} }{2}=-4.449\\\frac{4+\sqrt{24} }{2}=4.449\\[/tex]