aspenlei aspenlei

17-08-2017
Mathematics

contestada

If f(x) = x^2 - 4x + 1, find the range of f(x).

{y: y ≥ -3}
{y: y ≥ 13}
all reals

Respuesta :

ghanami ghanami

17-08-2017

hello :
y= x² - 4x + 1
calculate : x
y = (x²-4x+4)-4+1
y+3 = (x-2)²
x exist : if y+3 ≥ 0
y ≥ -3
the range is : {y: y ≥ -3}

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