1234cordelianaranjo 1234cordelianaranjo

16-08-2017
Mathematics

contestada

A rectangle has a length of x + 2, a width of 7, and a perimeter of 32.
The value of x is

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kphung76127 kphung76127

16-08-2017

Perimeter= 2(l+w)

32= 2((x+2)+7)
32= 2x+4+14
32= 2x+18
14= 2x
7=x

Final answer: x=7

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apologiabiology apologiabiology

16-08-2017

P=2(L+W)

L=x+2
W=7
P=32

32=2(x+2+7)
32=2(x+9)
divide both sides by 2
16=x+9
minus 9 both sides
7=x
x=7 units

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