Respuesta :

naǫ
[tex](-2,8) \\ x_1=-2 \\ y_1=8 \\ \\ (6,-2) \\ x_2=6 \\ y_2=-2 \\ \\ d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(6-(-2))^2+(-2-8)^2}= \\ =\sqrt{8^2+(-10)^2}=\sqrt{64+100}=\sqrt{164} \approx 12.8[/tex]

The distance is approximately 12.8 units.