Sure, to find the equation of the line passing through the origin (0, 0) and (3a, 5g), we can use the slope-intercept form of a line, which is:
y = mx + b
where m is the slope and b is the y-intercept.
To find the slope (m), we can use the formula:
m = (y2 - y1) / (x2 - x1)
So, plugging in the values, we have:
m = (5g - 0) / (3a - 0)
Simplifying this, we get:
m = (5g) / (3a)
Since the line passes through the origin, the y-intercept (b) is 0.
Therefore, the equation of the line is:
y = (5g/3a)x
