Respuesta :
[tex]\bf \begin{array}{rllll}
(6&,&3)&f(x)\\
x&&y\\\\
(-\frac{1}{2}x&,&3)&f(-\frac{1}{2}x)\\\\
(-\frac{1}{2}\cdot 6&,&3)\\\\
(-3&,&3)
\end{array}[/tex]
keep in mind that, a negative coefficient to "x", will make the graph reflect over the y-axis.
keep in mind that, a negative coefficient to "x", will make the graph reflect over the y-axis.
Answer:
this answer is wrong on plato, trust me
Step-by-step explanation:
