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20-06-2017
Chemistry

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What volume is occupied by 0.675 mol of CO2 at 226.2 K and 861 mmHg??

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dec77cat dec77cat

20-06-2017

PV=nRT

V=nRT/P

n=0.675 mol
T=226.2 K
P=861 mm Hg≈114790 Pa
R=8.31 J/(mol*K)

V=0.675*8.31*226.2/114790=0.01105 m³=11.05 L

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