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20-06-2017
Chemistry

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Find the pH of a 0.310 M aqueous benzoic acid solution. For benzoic acid, Ka=6.5⋅10−5.

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dec77cat dec77cat

20-06-2017

C=0.310 mol/L
Ka=6.5·10⁻⁵

pH=-lg√(C·Ka)

pH=-lg√(0.310·6.5·10⁻⁵)=2.35

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