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What is the value of  sinθ, given that cosθ=−2/5 and  sinθ>0?

Simplify radicals and rationalize the denominator, if necessary.

 

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sinθ=

Respuesta :

LammettHash
[tex]\cos\theta=-\dfrac25[/tex]
[tex]\sin\theta=\pm\sqrt{1-\cos^2\theta}=\pm\dfrac{\sqrt{21}}5[/tex]

Take the positive root, since it's given that [tex]\sin\theta>0[/tex].

[tex]\sin\theta=\dfrac{\sqrt{21}}5[/tex]

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