Respuesta :
					                   187 jumping jacks in total
60 for each of the first 2 days
y=number of jumping jacks on day 3
187=y+2(60)
187-2(60)=y
Solution: B. y=187-(60×2)
					                
					             60 for each of the first 2 days
y=number of jumping jacks on day 3
187=y+2(60)
187-2(60)=y
Solution: B. y=187-(60×2)
