Answer:
In exponential form given equation is expressed as [tex]b^x=y[/tex]
Step-by-step explanation:
Given equation is [tex]x=log_b\,y[/tex]
We use the following logarithmic result,
[tex]a^{log_a\,x}=x[/tex]
Consider,
[tex]x=log_b\,y[/tex]
Take both to the power of b.
[tex]b^{x}=b^{log_b\,y}[/tex]
[tex]b^x=y[/tex]
Therefore, In exponential form given equation is expressed as [tex]b^x=y[/tex]
