Respuesta :

Swastik1998
Answer(C)

√(9x^2)= 3x
√(18y^2)=3y/√2= 3y/√2 X √2/√2
=3√2y/2
mjankiewicz

[tex]\frac{\sqrt{9x^2}}{\sqrt{18y^2}}=\frac{x\sqrt{3^2}}{y\sqrt{3^2*2}}=\frac{\not3x}{\not3y\sqrt2}=\frac{x}{y\sqrt2}=\frac{x}{y\sqrt2}*\frac{\sqrt2}{\sqrt2}=\frac{x\sqrt2}{2y}[/tex]
Answer = C

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