Answer:
The answer is the option C
[tex]\frac{8}{17}[/tex]
Step-by-step explanation:
we know that
In the right triangle of the figure
Let
x-------> opposite side angle [tex]28\°[/tex]
y-----> hypotenuse
[tex]sin(28\°)=\frac{x}{y}[/tex]
in this problem we have
[tex]x=8\ units[/tex]
[tex]y=17\ units[/tex]
substitute the values
[tex]sin(28\°)=\frac{8}{17}[/tex]
