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HELP!!!! please :(
Find the first six terms of the sequence.
a1 = -3, an = 2 times an-1

The answer choices are:
A. -6, -12, -24, -48, -96, -192
B. -3, -6, -12, -24, -48, -96
C. 0, 2, -6, -4, -2, 0
D. -3, -6, -4, -2, 0, 2

HELP please Find the first six terms of the sequence a1 3 an 2 times an1 The answer choices are A 6 12 24 48 96 192 B 3 6 12 24 48 96 C 0 2 6 4 2 0 D 3 6 4 2 0 class=

Respuesta :

your sequence starts with -3 and multiplies every time by 2
so
B) -3, -6, -12, -24, -48, -96
is correct
irspow
This is a geometric sequence because each term is 2 times the previous term, called the common ratio, or "r" and it always has the form:

a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number, and in this case:

a(n)=-3(2^(n-1)) so the first six terms are:

-3,-6,-12,-24,-48,-96

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