littlelove6711 littlelove6711

21-04-2017
Mathematics

contestada

which is an equation of the line containing the points (4 10) and (6 11) in standard form

a) -x+2y=16
b) 2x-y=-2
c) x+2y=24
d) x-2y=-16

Respuesta :

liemonder liemonder

21-04-2017

Your slope m=(11-10)/(6-4)=1/2

y-Px=m*(x-Py)
insert the point (4,10):

=y-10=1/2(x-4)
=y-10=x/2-2
=y-x/2=8
formula*2=
a) =-x+2y=16

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