ewright18 ewright18

16-04-2017
Mathematics

contestada

Which equation has the same solutions as 2x^2+16x-10=0 a) (x+4)^2=-3 b) (x+4)^2=-11 c) (x+4)^2=13 d) (x+4)^2=21

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ghanami ghanami

16-04-2017

hello here is a solution :

Ver imagen ghanami

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Аноним Аноним

17-04-2017

2x^2 + 16x - 10 = 0
2(x^2 + 8x) - 10 = 0
2 [(x + 4)^2 - 16 ]- 10 = 0
[(x + 4)^2 - 16 - 5 = 0
(x + 4)^2 - 21 = 0
(x + 4)^2 = 21

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