contestada

suppose set a contains 39 elements and the total number elements in either set a or set b is 80. if the sets a and b have 1 elements in common, how many elements are contained in set b?

Respuesta :

mhanifa

Answer:

  • 42 elements

-----------------------

Using the formula for the union of two sets:

  • |A ∪ B| = |A| + |B| - |A ∩ B|

where

  • |A| represents the number of elements in set A,
  • |B| represents the number of elements in set B, and
  • |A ∩ B| represents the number of elements in both sets A and B.

We are given that:

  • |A| = 39
  • |A ∩ B| = 1
  • |A ∪ B| = 80

Plugging in the values, we get:

  • 80 = 39 + |B| - 1
  • |B| = 80 - 38
  • |B| = 42

Therefore, set B contains 42 elements.

Otras preguntas