Respuesta :
					                   [tex]x( \theta) =  \frac{v_0^{2} sin(2\theta)}{g}  \\  \\  \frac{dx}{d \theta} = - \frac{ 2v_0^{2} }{g} cos(2 \theta) = 0 \\  \\ 2 \theta =  \frac{ \pi}{2}  \\ \\   \theta  =  \frac{ \pi}{4}  \\  \\ x_m_a_x = x( \frac{ \pi}{4} )= \frac{v_0^{2} sin( \frac{ \pi}{2} )}{g}[/tex]
					                
					                
					             