ba6lleyMonnibeibeck ba6lleyMonnibeibeck
  • 19-03-2017
  • Physics
contestada

What is the moment of inertia of an object that rolls without slipping down a 2.00-m-high incline starting from rest, and has a final velocity of 6.00 m/s?

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Аноним Аноним
  • 19-03-2017
[tex]E = mgh + \frac{1}2} m v^{2} + \frac{1}{2} I \omega^{2} = mgh + \frac{1}2} m r ^{2} \omega ^{2} + \frac{1}{2} I \omega^{2} [/tex]

for a solid cylinder:  [tex]I = \frac{1}{2} m r^{2} [/tex]
for a hollow cylinder: [tex]I = mr^{2} [/tex]

I will look at the case of a hollow cylinder:

[tex]E = mgh + I \omega ^{2} = constant \\ \\ I = \frac{mgh}{ \omega^{2} }[/tex]

That is as far as i get.


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