f is a quadratic function whose graph is a parabola opening upward and has a vertex on the x-axis. The graph of the new function g defined by g(x) = 2 - f(x - 5) has a range defined by the interval
A. [ -5 , + infinity)
B. [ 2 , + infinity)
C. ( - infinity , 2]
D. ( - infinity , 0]
to move a function c units up, add c to the whole function to reflect the function over the x axis, times the whole function by -1 to move the graph c units to the right, minus c from every x
we got from f(x) we minused 5 from every x to get f(x-5) moved graph 5 units to right then we multiplied by -1 to reflect across the x axis to get -f(x-5) then we added 2 to the whole thing to move it up 2 units to get 2-f(x-5)
so
range=lowest y value to highest y value original paraobla opend up so original range is 0 to infinity the original parabola was move 5 to the right, reflected across the x axis then moved up 2 units originally, the vertex was on the x axis so range is not affected then we reflected across x axis so now range is negative infinity to 0 then we moved up 2 units now range is negative infity to 2
so answer si C with a movement 5 to the right, the vertex is still on the x axis
