Not including myself and 1, my factors are 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48. What number am I?

Question

21-02-2017
Mathematics

contestada

Not including myself and 1, my factors are 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48. What number am I?

Respuesta :

Otras preguntas

According to the map above, all of the following areas have a high population density except __________. A. eastern China B. Japan C. North and South Korea D. c

How can substances in a compound and in a mixture be separated?

How did medieval society view women

770 x 6 = 77 x 6 x 100 True or False?

what is 5+4 help please

what is this -5g-13g=54?

what relationship if any between diameter and circumferenceyytr

Jacob is ordering custom T-shirts for his soccer team. Long-sleeved shirts cost $15 each and short-sleeved shirts cost $10 each. Jacob can spend at most $250 an

The history and culture of easter island is most closely tied to _____________.

what conflict Is leiningen facing

ahonyek ahonyek · Answer 1 · 2017-02-21T17:37:48+01:00

ahonyek ahonyek

21-02-2017

2=2
3=3
4=2*2
6=2*3
8=2*2*2
12=2*2*3
16=2*2*2*2
24=2*2*2*3
32=2*2*2*2*2
48=2*2*2*2*3

This is called the prime factors of these numbers. As you can see 3 only appears once for a single number. The maximum number of 2s is 5.
Thus the solution is 2*2*2*2*2*3=96

Answer Link

Аноним Аноним · Answer 2 · 2017-02-21T22:53:20+01:00

Аноним Аноним

21-02-2017

2=2
3=3
4=2*2
6=2*3
8=2*2*2
12=2*2*3
16=2*2*2*2
24=2*2*2*3
32=2*2*2*2*2
48=2*2*2*2*3

Answer Link