a) by looking at the graph it took her 650 sec to get to training.
b) the student did walk to training at a steady speed bc the slope of the line represents the velocity ( or speed), and the line is linear rather than polynomial or curved.
c) average speed = change in position( displacement) / change in time
final position- initial position / final time -initial time
0m-0m = 0 m OR -450m - +450m =0m
650sec-0sec = 650 sec
0/650 =0m/s
answer to c is 0 m/s
> this makes sense bc the velocity is constant meaning there wouldn’t be a slope on a velocity time graph.
