sadziprincess52
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  • 20-08-2022
  • Mathematics
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point p to Point q is 15 km away and on a bearing of 090°to a point R is 8 km from q. find the distance between p and r​

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jdoe0001 jdoe0001
  • 20-08-2022

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[tex]\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2 + b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{RP}\\ a=\stackrel{adjacent}{15}\\ b=\stackrel{opposite}{8}\\ \end{cases} \\\\\\ RP=\sqrt{15^2+8^2}\implies RP=\sqrt{225+64}\implies RP=17[/tex]

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