7.5 × 10¹⁹ Electrons flow through a point in a wire in 3.00 s if there is a constant current of i=4.00a.
Q = I × t------------Equation 1
Where Q = charge flowing through the wire, I = current, t = time
Given: I = 4.00 A, t = 3.00 s
Substitute these values into equation 1
Q = 4.00× 3.00
Q = 12.00 C.
But,
1 electron contains 1.6×10⁻¹⁹ C
therefore,
12.00 C = 12.00/1.6×10⁻¹⁹ electrons
= 7.5 × 10¹⁹ Electrons
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