Step-by-step explanation:
1st expression ,
[tex] 2 {x}^{2} + x - 3[/tex]
[tex]2 {x}^{2} + (3 - 2)x - 3[/tex]
[tex]2 {x}^{2} + 3x - 2x - 3[/tex]
[tex]x(2x + 3) - 1(2x + 3)[/tex]
[tex](x - 1) \: (2x + 3)[/tex]
2nd expression
[tex]4 {x}^{2} - 9[/tex]
Using the formula
[tex] {a}^{2} - {b}^{2} = (a + b) \: (a - b)[/tex]
[tex](2x {)}^{2} - (3 {)}^{2} [/tex]
[tex](2x + 3) \: (2x - 3)[/tex]
Now ,
HCF = CF
HCF = ( 2x + 3 ) ...
