Answer:
area of A'B'C'D' = 18.4 units²
Step-by-step explanation:
given 2 similar figures with
ratio of corresponding sides = a : b , then
ratio of areas = a² : b²
here ratio of sides = 5 : 2
ratio of areas = 5² : 2² = 25 : 4
let x be the area of A'B'C'D' , then by proportion
[tex]\frac{25}{115}[/tex] = [tex]\frac{4}{x}[/tex] ( cross- multiply )
25x = 460 ( divide both sides by 25 )
x = 18.4
area of A'B'C'D' = 18.4 units²
