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Two individuals who are heterozygous for Huntington’s are pregnant with a child. What is the probability that the resulting child will not inherit Huntington’s disease ?

Calculate the probability. The Punnett square is provided to show your work

Two individuals who are heterozygous for Huntingtons are pregnant with a child What is the probability that the resulting child will not inherit Huntingtons dis class=

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The probability that the resulting child will not inherit the disease is 25%.

Probability in genetics

Assuming that the disease is represented by the allele A (a). Huntington's disease is autosomal dominant.

Thus, the genotypes of the two parents will be Aa each.

    Aa    x    Aa

   AA   Aa   Aa   aa

Probability of the child having Huntington's = 3/4 or 75%

Probability of the child not having Huntington's = 1/4 or 25%

More on Huntington's can be found here: https://brainly.com/question/12572808

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